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解方程2(x+1.7)=9.2

(1)2(x+1.7)=9.2, 2(x+1.7)=9.2÷2, x+1.7=4.6,x+1.7-1.7=4.6-1.7x=2.9;(2)8x-4x=0.64, 4x=0.64,, 4x÷4=0.64÷4,x=0.16; (3)2x-0.24=0.12,2x-0.24+0.24=0.24+0.12, 2x=0.36, 2x÷2=0.36÷2x=0.18;(4)6.2x-x=416, 5.2x=41...

①(x+1.7)×2=9.2, (x+1.7)×2÷2=9.2÷2, x+1.7=4.6, x+1.7-1.7=4.6-1.7, x=2.9;②8x-4x=0.64,x(8-4)=0.64, 4x=0.64, 4x÷4=0.64÷4, x=0.16;③2x-0.24=0.12,2x-0.24+0.24=0.12+0.24, 2x=0.36, 2x÷2=0.36÷2, x=0.18;④7x+2.5X=3.8...

x+1.7=9.2÷2=4.6 x=4.6-1.7=2.9

2(x➕1)➕7=15 解 2x➕2➕7=15 2x=15➖7➖2 2x=6 x=3

x+1.7=19.2*1.2-0.6 x=19.2*1.2-0.6-1.7

计算 1.9(x+0.5)=1.7(x+3.2) 1.9x+0.95=1.7x+5.44 x=(5.44-0.95)/(1.9-1.7) =4.49/0.2 =22.45

解:-4+2x-3+6x=7-7x+10-5x 2x+6x+7x+5x=7+10+4+3 20x=24 x=1.2

1/7(X-1)=2/21(X+3.6-1) 先解出来,就是去括号和移项, 得到 14x-14=21x+54.6 那么就可以解出来 x=-9.8 这时两车相距全程的3\7,那么就可以说明说2小时内,两车总共行了全程4/7,因为我们把全程当作1看, 设客车速度为2X,货车速度就是3X (2X+3X)*2...

2.43+x=4.6 x=4.6-2.43 x=2.17 3.2-x=1.23 3.2-1.23=x x=1.97 x-1.7=12.5 x=12.5+1.7 x=14.2 x+3.25=9.04 x=9.04-3.25 x=5.79

解:两边同时乘以21 7(x-1)=3(x+1) 7x-7=3x+3 7x-3x=3+7 4x=10 x=2.5

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