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5/6除以括号1/8加1/12括回

5/6÷(1/8+1/12) =5/6÷5/24 =4

(5/6-1/8-1/12)x4.8 =(5/6-1/8-1/12)x48/10 =5/6x48/10-1/8x48/10-1/12x48/10 =4-4/5-2/5 =4-6/5 =14/5

一加二的零次方等于二,二加二的一次方等于六,就是找二的n次方的规律,42之后是42加上二的五次方,所以填74

7/8-括号5/12+1/6括回脱式计算 (7/8)-(5/12+1/6) =(7/8)-(7/12) =(21/24)-(14/24) =7/24.

=24x3/8x1/6+24x5/12 =3/2+10 =23/2

-10

括号3/4-1/8括号y除以5/12怎么算 (3/4-1/8)y÷(5/12) =(5/8)y×(12/5) =(3/2)y.

原式=(3/8+1/6+5/12)*24 =3/8*24+1/6*21+5/12*24 =9+4+10 =23

-24×(5/6-3/8+1/12) =-24×5/6+24×3/8-24×1/12 =-20+9-2 =-13

负十三分之一 (-1/13)

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